Suppose ${Omega_k}_{k=1}^{infty}$ is a sequence of sets, where $Omega_k$ is countably infinite and $Omega_{k+1}subsetOmega_k$ for all $k$. Is it possible to show that $cap _{k=1}^{infty} Omega_k$ is countably infinite?
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Suppose ${Omega_k}_{k=1}^{infty}$ is a sequence of sets, where $Omega_k$ is countably infinite and $Omega_{k+1}subsetOmega_k$ for all $k$. Is it possible to show that $cap _{k=1}^{infty} Omega_k$ is countably infinite?